I didn't pose the question on FB, I just did the math, roughly as Vigilante posed. If you extrapolate from there, 390,000 in^3 is the volume of a 45 inch radius sphere, or 7.5' diameter.The Vigilante wrote:First of all, using imperial measurements is retarded, learn metric.Prak_Anima wrote:How sure are you, virgil? When I posed the question on Facebook, I got this:Facebook wrote:Density = m/V = 1kg /48 in^3, thus the volume of a 9-ton spheroid mass would be
V = m/d = (9 tons * 907 kg/ton)/ (1/48 kg/in^3) = 390,000 in^3
48 cubic inches = 787 cm3 roughly, which gives us a density of 1,27 g/cm3. I assume you use US tons, which are equivalent to 907kg roughly, or 907 000g. Since V = M/D, this gives us a volume of 714 173 cm3 for a one US ton boulder, or 6 427 557 cm3 for a 9 ton boulder ; which translates to roughly 227 cubic feet. This would make it a 7.5 feet high boulder.
So yes, everyone is right
![Sick :P](./images/smilies/sick.gif)