Elennsar, this is your last chance to not get put on permanent ignore. Wrap your mind around this or GTFO.
Iterative Probability: Sets
OK, we're going to talk about these things in terms of coin flips because it is easy. It is important to note that the chances of something happening are always 1. That is while you can land a coin heads half the time and tails half the time, the chance of landing heads or tails is 100%. When you have disjoint events like that, the probabilities do in fact add. But when you're talking about multiple events happening in series, the action tends to be multiplication. Since probability is set in terms of fractions, when you multiply things together they become more unlikely. Getting a head is something that happens 1/2 the time. Getting a head on both flips in your set is something that happens (1/2)*(1/2) = 1/4 of the time.
If you have a situation where you are looking for the chances of one thing happening or (inclusive) another thing happening, it is usually best to find the chances of neither event occurring and subtracting that chance from 1. Remember that chances of any of the set of all possible events happening are always going to add up to 1 because something happens all the time. So your chance of getting at least 1 Head in your set of two flips is easiest found by subtracting your chance of getting Tails on both flips, and then subtracting from 1. So 1 - (1/2) * (1/2) = 3/4. 75% of the time your set will have at least one Head.
The other thing that is important is that our set can be defined however we want to define it. It seriously doesn't matter. Any two flips that haven't been flipped yet have a 1/4 chance of getting two Heads, a 3/4 chance of getting at least 1 Head, and a 1/4 chance of getting 2 Tails. And that adds up to more than 1 because you can't add the chances of getting 2 Heads to the chance of getting at least 1 Head because the chance of getting at least 1 Head already includes the chance of getting both Heads. You can plot those chances out manually by writing down all four combinations (events with at least one Head in them are bolded):
- HH
HT
TH
TT
Imagine for the moment that you flip a coin twenty times in a row. If for whatever reason we are concerned about the 3rd and 15th flip, their chances of both coming up Heads are one in four. If for whatever reason we're concerned about the 10th and 20th, the chances of them both coming up Heads are still one in four. And here's the really really important part: if you define your set by some variable criteria, the chances are still one in four. So if you check the first two flips after someone burps, the chances of them both being Heads are 1 in 4. And the first 2 flips after you get a Head, the chances are still 1 in 4. Yes, even tough that's 3 Heads in a row, the chances are 1 in 4, because only the last 2 of them are actually in the set. You could have gotten a Head on your first flip and then started counting to see if you got 2 Heads in a row, or you could have flipped Tails 16 times in a row before you got a Head and started counting. It doesn't make any difference. That first Head is just a sign post, the set whose probability you are calculating is still just 2 flips.
Selection Bias
The chances of things having turned out the way they did is 100%. Always. No matter how weird the data set seems. You were always going to end up with a result, and the one you got is just the one you got. Every coin you have already flipped no longer has a 50% chance of landing Heads and a similar chance of landing Tails, it has a 100% chance of having landed whichever way it happened to come up.
Let's take the ultimate game of Selection Bias: Let's Make a Deal. Here's how it works: Monty Haul shows you three doors, behind one of which is a prize. You pick one of the doors, (let's say #2 for this example). Then Monty Haul opens one of the other doors (either #1 or #3 in this example) and shows you an area with no prize. Now you are offered the chance to stay on the door you originally picked, or switch to the remaining door.
As it happens, you should switch to the remaining door because of selection bias. The door you originally picked had only a 1 in 3 chance of having the prize. And it still does because nothing has happened to that door to change it. The door Monty showed you the contents of is not random. It's always going to be empty. Which means that if the Prize was behind door #3, he'll open door #1. If the prize is behind door #1, he'll open door #3. So if the prize is behind Door #1 or #3, you'll get the prize if you switch doors. If it was behind door #2, you'll get it if you stay with your original selection. So even though you only have two choices, your chances are not 50/50 because there are additional non-random elements. Your chances are nonetheless calculable, because the effects of the non-random elements are known. The odds are 33% if you stay with your original selection, and 67% if you switch.
How This Affects Game Design
Events can be calculated separately or together. Your chances of making an Appraise flip can be isolated from all your other coin flips simply by announcing that you are doing so. Your chance of flipping Heads on your first Appraise flip is 50%. We can say that with complete confidence even if we don't know how many flips will happen before or after it and don't know what the previous flips actually are.
The set, in that case, is simply one flip. And it has on its own a 50/50 shot of coming up Heads or Tails. If we link it into a set with another flip, then our set is two flips long, and follows the rules for two flip sets above. And no, it doesn't make any difference what the specific criteria of us having two flips in our set are. They could be the first two Attack flips, the first two enemy attack flips, the third appraise flip and the second jump flip. Whatever. Indeed, it could even be something incredibly arcane like the first two flips that meet the criteria of being the first flip after an an enemy has flipped three Heads in a row during an attack cycle. It doesn't matter. Two flips, however they are defined ahead of time, have a 1 in four chance of coming up Heads. And a 3/4 chance of coming up with at least one Head.
-Username17